In this case the answer is very simple. .
We must analyze the graph to find the solution.
Step 01:
Data
Triangle ABC
point A (1,1)
point B (4,0)
point C (3,3)
Step 02:
Traslation (x,y) ==> (x - 1, y - 2)
A' ( 1 - 1 , 1 - 2 )
A' ( 0 , - 1)
B' ( 4 - 1 , 0 - 2 )
B' ( 3 , -2 )
C' ( 3 - 1, 3 - 2 )
C' ( 2 , 1)
Step 03:
We must compare the calculated coordinates of the new points to verify if they coincide with those of the graph.
Triangle A'B'C'
Graph Calculated
A' (2, 3 ) ≠ A' ( 0 , - 1)
B' ( 6,2 ) ≠ B' ( 3 , -2 )
C' ( 4 , 5) ≠ C' ( 2 , 1)
The answer is:
False. Because the calculated coordinates are different from the coordinates of the graph.