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Kavin made the 10 number cardsshown below.444N11997Gavin shuffled the cards and thenflipped them over so his friend Rickcould not see the numbers. If Rickrandomly chose one of the cards, hewas more likely to choose a card witha 4 than a card withA an odd numberB a prime numberC another even numberD an odd number less than 7

Kavin made the 10 number cardsshown below.444N11997Gavin shuffled the cards and thenflipped-example-1
User Alex Mamo
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1 Answer

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We have a total of 10 cards.

From these 10 cards, three cards are number 4, so the probability of choosing a number 4 is P = 3/10.

Calculating the probability for each option, we have:

A. Odd number

There are 6 odd numbers among the cards, so the probability is P = 6/10

B. Prime number

There are 3 prime numbers among the cards, so the probability is P = 3/10

C. Another even number

There are 4 even numbers among the cards, so the probability is P = 4/10

D. An odd number less than 7.

There are 3 odd numbers less than 7, so the probability is P = 3/10

The bigger probability is for an odd number, therefore the correct option is A.

User JackMahoney
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