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A car, initially at rest, accelerates at 8.7 m/s2 for a total of 9.7 s. How far did it go in this time?

1 Answer

1 vote

We can use the next formula


d=ut+(at^2)/(2)

where d is the distance, u is the initial velocity, a is the acceleration, t is the time.

In this case

u=0 m/s

a=8.7 m/s^2

t=9.7 s

we susbtitute


d=(0)(9.7)+((8.7)(9.7)^2)/(2)=409.3m

ANSWER

The distance is 409.3 m

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