Recall that for a, b, and c to be the lengths of a triangle they must satisfy the following inequalities:
![\begin{gathered} a+b>c, \\ a+c>b, \\ b+c>a\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3kvi0aji994f4keqgtwxa6omx0pe31dtun.png)
Therefore, if we call the other side x, it must satisfy that:
![\begin{gathered} 6+x>9, \\ 9+x>6, \\ 9+6>x\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qvlu6mxf3kpkwhdqb6f7zs8qgxc61pihed.png)
Solving each inequality for x, we get:
![\begin{gathered} x>9-6=3, \\ x>6-9=-3, \\ 15>x\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/wt1fup4696oqxmnq04trygf1ozqdj2ahfl.png)
Therefore, x must be greater than 3 inches but less than 15 inches.
Answer: The possible lengths of the third side must be greater than 3 inches but less than 15 inches