Question

i’m doing a pretest and i’m confused on this question, i haven’t learned this material. help please!!

Answer 1

Given:

`\begin{gathered} secB=(5)/(3) \\ a=16 \end{gathered}`

The Secant Function is given by:

`Sec=(hypothenuse)/(adjacent)`

Hence:

`(c)/(16)=(5)/(3)`

Solving for c:

`\begin{gathered} 3c=16*5 \\ c=(80)/(3) \end{gathered}`

ANSWER

The hypothenuse is 80/3