Question

What is the potential energy of a 0.75 kg apple sitting 3 m off the ground

Answer 1

Given data

*The given mass of the apple is m = 0.75 kg

*The given height is h = 3 m

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The formula for the potential energy is given as

`U_p=mgh`

Substitute the known values in the above expression as

`\begin{gathered} U_p=(0.75)(9.8)(3) \\ =22.05\text{ J} \end{gathered}`

Hence, the potential energy of a 0.75 kg apple sitting 3 m off the ground is U_p = 22.05 J