212k views
1 vote
Can you please help me out with a question

1 Answer

2 votes

In order to calculate the volume of the shaded portion, we shall take the following steps;


\begin{gathered} \text{Volume of cylinder-Volume of spheres} \\ For\text{ the cylinder;} \\ \text{Vol}=\pi* r^2* h \\ r=6,h=25 \\ \text{Vol}=\pi*6^2*25 \\ \text{Vol}=\pi*36*25 \\ \text{Vol}=900\pi \\ \text{For the sphere;} \\ \text{Vol}=(4)/(3)\pi* r^3 \\ \text{For two spheres, we shall now have,} \\ \text{Vol}=2*(4)/(3)*\pi*6^3 \\ \text{Vol}=(8)/(3)*216*\pi \\ \text{Vol}=576\pi \end{gathered}

Therefore, the volume of the shaded portion is derived as follows;


\begin{gathered} \text{Vol}=900\pi-576\pi \\ \text{Vol}=324\pi in^3 \end{gathered}

The answer is 324 pi cubic inches

User Zong
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories