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An advertiser rents a rectangular billboard that is 44 ft wide and 20 ft tall. the rent is $15 per square foot. for a billboard twice as tall, the advertiser has to pay $26,400. is this reasonable? explain.

An advertiser rents a rectangular billboard that is 44 ft wide and 20 ft tall. the-example-1
User Arminb
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1 Answer

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Yes; when the height is doubled, the area is also doubled (option D)

Step-by-step explanation:

width of the billboard = 44 ft

height of the billboard = 20 ft

the rent per square ft = $15

for a billboard twice as tall, the advertiser has to pay $26,400

We need to find the area of the billboard = width × height

Area = 44 × 20

Area of the billboard = 880 ft²

The rent for the whole area of the billboard = $15 × 880

The rent for the whole area of the billboard = $13,200

when the height is doubled = 2(height)

new height = 2(20) = 40 ft

The new area = 44 × 40 = 1760 ft²

The rent for the new area of the billboard = $15 × 1760

The rent for the new area of the billboard = $26400

The result in our calculation is the same as the amount the advertiser payed.

new height = 2(old height)

new area = 2(old area)

26400 = 2(13200)

We can conclude: it is reasonable

Yes; when the height is doubled, the area is also doubled (option D)

User Chris Mantle
by
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