Question

The probability of choosing two green balls without replacement is 111, and the probability of choosing one green ball is 13.What is the probability of drawing a second green ball, given that the first ball is green?

Answer 1

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given probabilities

`\begin{gathered} Pr(2\text{ greens\rparen}=(1)/(11) \\ Pr(one\text{ green\rparen}=(1)/(3) \end{gathered}`

STEP 2: Write the probability formula for probability of second green given first green

`\begin{gathered} Pr(G2|G1)=\frac{Pr(2\text{ greens\rparen}}{Pr(one\text{ green\rparen}} \\ =(1)/((11)/((1)/(3)))=(1)/(11)/(1)/(3)=(1)/(11)*(3)/(1)=(3)/(11) \end{gathered}`

Hence, the answer is 3/11