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A large rectangle has an area of 5x^2 + 3x - 2. If I place a smaller rectangle, with an area of 2x^2 + x + 6, over the larger rectangle. What area of the larger rectangle will still be visible?
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35 votes
35 votes
A large rectangle has an area of 5x^2 + 3x - 2. If I place a smaller rectangle, with an area of 2x^2 + x + 6, over the larger rectangle. What area of the larger rectangle will still be visible?

User Vinit Kantrod
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1 Answer

17 votes
17 votes

Answer:

(5x^2 + 3x - 2) - (2x^2 + x + 6) = 3x^2 + 2x - 8

Explanation:

User Vlad Havriuk
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