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2. A capacitor has a capacitance of 1.50 x 10-10 F. How much charge is stored when the potential difference is 1.75 V?

User EWit
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1 Answer

3 votes

The charge in a capacitor is given by:


Q=CV

plugging the values given we have that:


\begin{gathered} Q=(1.5*10^(-10))(1.75) \\ Q=2.625*10^(-10) \end{gathered}

Therefore the charge in the capacitor is:


2.625*10^(-10)\text{ C}

User Adamj
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