Question

A bicyclist rides 11.2 kilometerseast and then 5.3 kilometers southWhat is the angle of thebicyclist's resultant vector?

Answer 1

Given

A = 11.2 km East

B = 5.3 km south

Find

Angle of the resultant vector

Step-by-step explanation

Angle of the resultant vector is given by

`tan\emptyset=(Bsin\alpha)/(A+Bcos\alpha)`

Here angle between both the vectors is 90 degree

`\begin{gathered} tan\emptyset=(Bsin\alpha)/(A+Bcos\alpha)=(11.2(sin90))/(5.3+11.2(cos90)) \\ tan\emptyset=(11.2)/(5.3) \\ tan\emptyset=2.11320755 \\ \emptyset=64.67degrees \end{gathered}`

So Angle made from origin = 270+64.67

= 334.67 degree = 334.7 degree(approx)

Final Answer

Angle of resultant Vector = 334.7 degree