Question

X= 1/2, y=4, z=1/420z+y3+40x(x-z)

Answer 1

we want to find;

`\begin{gathered} 20z+y^3+40x(x-z)\text{ -----(1)} \\ \text{ sustituting }x=(1)/(2);\text{ }y=4;\text{ }z=(1)/(4)\text{ in eqation (1)} \\ \Rightarrow20z+y^3+40x(x-z)=20((1)/(4))+(4)^3+40((1)/(2))((1)/(2)-(1)/(4))=5+64+5 \\ \end{gathered}`

Therefore, 20z+ y^3 + 40x(x-z) = 74.