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1 vote
SandwichSideDrinkJr. Bacon Cheeseburger(65%) Fries (63%)Coke(33%)Crispy Chicken Sandwich(35%) Salad (17%)Diet Coke(18%)Baked Potato (20%) Dr. Pepper (26%)Sprite (23%)So based on these sales numbers, whatare the odds that the next customerorders a Jr. Bacon Cheeseburger, fries orpotato, and a Dr. Pepper?

User Merus
by
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1 Answer

7 votes

It is given that the probability of odering a Cheeseburger, fries or potato, and a Dr. Pepper is given by:


\begin{gathered} P(A)=P(C)*(P(F)+P(P))* P(DP) \\ P(A)=0.65*(0.63+0.2)*0.26 \\ P(A)=0.14027 \end{gathered}

Hence the probability is 14%.

Option B is correct.

User Bckpwrld
by
4.1k points