Question

Net ionic equation for SrBr2 + K2SO4 --->

Answer 1

`2K^+\text{ + 2Br}^-\text{ }\rightarrow\text{ 2KBr}_((s))`

Step-by-step explanation:

Here, we want to write the net ionic equation for the given equation;

`SrBr_2\text{ + K}_2SO_4\text{ }\rightarrow\text{ SrSO}_4\text{ + 2KBr}`

Now, what is left is to write the participating ions:

`Sr^(2+)\text{ + 2Br}^-\text{ + 2K}^+\text{ + SO}_4^(2-)\text{ }\rightarrow\text{ Sr}^(2+)\text{ + SO}_4^(2-)\text{ + 2KBr}`

We must identify that the Potassium Bromide is the precipitate and thus would not be dissociated into ions

Thus, we have it that:

The Strontium ion cancels out, including the sulphate

We have left:

`2K^+\text{ + 2Br}^-\text{ }\rightarrow\text{ 2KBr}`