The depreciation equation is given by
![f(x)=27000(0.86^x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5bzt6ns92hek6zkh7sy2qad3n0h2xdoy5g.png)
where x represents the number of years. Here, the initial value of the car corresponds to x=0, then we have
![\text{ initial value = f\lparen0\rparen=27000}](https://img.qammunity.org/2023/formulas/mathematics/high-school/fcjyxojbga9jvasadi71pq37llkj4z7km3.png)
After one year, the car value corresponds to x=1, that is,
![\text{ after 1 year = f\lparen1\rparen=27000\lparen0.86}\rparen^1\text{=27000}*0.86=\text{23220}](https://img.qammunity.org/2023/formulas/mathematics/high-school/7irnhq15eib2u1osaah365blfvddyif3iq.png)
Now, let's find the depreciation percentage by means of a rule of three:
![\begin{gathered} 2700\text{ ----- 100 \%} \\ 23220\text{ ------- x} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gamrbit2i0j7pheu4pw0ls0j7rmb646508.png)
so we have
![x=(23220*100)/(27000)=86\text{ \%}](https://img.qammunity.org/2023/formulas/mathematics/high-school/m0d3asn9g0pzwf4n9k45h8qoqdekw5ib6u.png)
So the difference between 100% and 86% is 14% This means Nichole's car depreciate 14% each year