221k views
0 votes
Y= 2x^2 +6x+11In vertex form

User Rehumbus
by
6.2k points

1 Answer

3 votes

Given:


y=2x^2+6x+11
y=2(x^2+3x+(11)/(2))
y=2(x^2+3x+(9)/(4)-(9)/(4)+(11)/(2))
y=2(x^2+3x+((3)/(2))^2)-(9)/(2)+(22)/(2)
y=2(x+(3)/(2)^{})^2+(13)/(2)

Above equation is the vertex form.

User Hooda
by
5.6k points