Question

Calculate the potential difference across a 10 ohm register carrying a current of 2.5 ampere

Answer 1

Given information:

Resistance of the resistor;

`R=10\text{ }\Omega`

Current through the resistor;

`I=2.5\text{ A}`

According to Ohm's law, the potential difference is given as,

`V=IR`

Substituting all known values,

`\begin{gathered} V=(2.5\text{ A})*(10\text{ }\Omega) \\ =25\text{ V} \end{gathered}`

Therefore, the potential difference across a 10 Ω resistor carrying a current of 2.5 A is 25 V.