To solve this problem we will use the formula for compound interest:
![P_N=P_0\cdot(1+(r)/(k))^N\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/tditkdnll8hzldlenuw20qakunverxq23e.png)
Where:
• P_N is the balance in the account after N years,
,
• P_0 is the starting balance of the account (also called an initial deposit, or principal),
,
• r is the annual interest rate in decimal form,
,
• N in years,
,
• k is the number of compounding periods in one year.
In this problem, we have:
• P_0 = $328,120,,
,
• interest P_N - P_0 = $23,515.27 → ,P_N = $351,635.27,,
,
• N = ,200 days = ,200/365,
,
• k = 1.
From the formula above, we have:
![\begin{gathered} ((P_N)/(P_0))^{(1)/(N)}=1+r \\ r=((P_N)/(P_0))^{(1)/(N)}-1. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/lh3ou593xejpetd8hrgcbroa0uq6t7rr44.png)
Replacing the data of the problem, we get:
![r=((351,635.27)/(328,120))^{(365)/(200)}-1\cong0.1346\cong13.5%.](https://img.qammunity.org/2023/formulas/mathematics/college/ixrbq27x1xv8p4puaqaly7lu0xvdgz50ej.png)
Answer
The annual interest is 13.5%.