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Find the perimeter and area.and then round to the nearest tenth

Find the perimeter and area.and then round to the nearest tenth-example-1
User Djzin
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Answer: Perimeter 88.3 cm

Area 375 sq cm

Step by step explanation:

The perimeter of a triangle is queal to the sum of all the sides. In the figure we have an isosceles triangle (2 sides equal), to find the perimeter we must find the length of the equal sides:

From Pythagorean Theorem we have:


\begin{gathered} h^2=a^2+b^2 \\ h^2=25^2+15^2 \\ h=\sqrt[]{850}=5\sqrt[]{34} \end{gathered}

The perimeter is:


\begin{gathered} P=2\cdot15+5\sqrt[]{34}+5\sqrt[]{34} \\ P=30+5\sqrt[]{34}+5\sqrt[]{34} \\ P=88.309\approx88.3\operatorname{cm} \end{gathered}

The area of a triangle can be calculated using the formula:


A=(1)/(2)base* perpendicularheight

base = 2*15 = 30 cm

Perpendicular height = 25 cm


\begin{gathered} A=(1)/(2)\cdot30*25 \\ A=375\operatorname{cm} \end{gathered}

Perimeter = 88.3 cm

Area = 375 sq cm

Find the perimeter and area.and then round to the nearest tenth-example-1
User Bjorkblom
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