Question

Find the real and or complex solutionsx^3-3x^2+2x=0

Answer 1

Your answers are X=0,1,2

Answer 2

Given:

`x^3-3x^2+2x=0`

To determine the solutions, we find the factors of the given function. So,

`\begin{gathered} x^3-3x^2+2x=0 \\ \text{Simplify} \\ x(x^2-3x+2)=0 \\ \end{gathered}`

Next, we factor x^2-3x+2=0:

`\begin{gathered} x(x^2-3x+2)=0 \\ x(x-2)(x-1)=0 \end{gathered}`

Then,we find the values of x:

x=0

x-2=0

x=2

x-1=0

x=1

Therefore, the solutions are:

x=0, x=1, x=2