Question

These marbles are placed in a bag and twoof them are randomly drawn.What is the probability of drawing two pinkmarbles if the first one is placed back in thebag before the second draw?Give your answer as a ratio, reduced tosimplest terms.Hint: Multiply the probability of the 1st Event by theprobability of the 2nd Event to get your answer.

Answer 1

Let's begin by listing the information given us:

Yellow marble = 2

Pink marble = 3

Blue marble = 5

Total marble = 2 + 3 + 5 = 10

The probability of picking two pink marbles if the first one is placed back in the bag is given by:

`\begin{gathered} P(pink_1)=(No.Of.Pink)/(Total)=(3)/(10) \\ P(pink_1)=(3)/(10) \\ \text{After placing the pink marble back, the proba}bility\text{ of picking Pink again is:} \\ P(pink_2)=(No.Of.Pink)/(Total)=(3)/(10)_{} \\ P(pink_2)=(3)/(10) \\ P(event)=P(pink_1)* P(pink_2)=(3)/(10)*(3)/(10)_{} \\ P(event)=(9)/(100)=9\colon100 \\ \\ \therefore P(event)9\colon100 \end{gathered}`