Given data
The mass of the student is m = 60 kg
The kinetic energy possessed by the car is KE = 1.2 x 104 J
The expression for the kinetic energy of the car is given as:
![\begin{gathered} KE=(1)/(2)mv^2\ldots.\ldots.(1) \\ v=\sqrt[]{(2* KE)/(m)} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/bhucbfgxtrm5vrg6qu5rntp2yz5wgs5cvo.png)
Here, the velocity of the car is taken as v.
Substitute the value in the above equation.
![\begin{gathered} v=\sqrt[]{\frac{2*1.2*10^4\text{ J}}{60\text{ kg}}} \\ v=20\text{ m/s} \\ v=20\text{ }(m)/(s)*\frac{1\text{ km}}{1000\text{ m}}*\frac{3600\text{ s}}{1\text{ h}} \\ v=72\text{ km/h} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/8188lo8m3a23ym7s2btkzgkxkg0ukxs9z8.png)
Thus, the car speedometer reading is 72 km/h.