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(7x^2+2x-3) - (4x^2 - 3x +1)

User Paredes
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1 Answer

3 votes

We want to calculate the following expression


(7x^2+2x-3)-(4x^2-3x+1)

We will begin by eliminating the parentheses from the expression. To do so we need to distribute the negative sign of the right most parentheses. If we do so we obtain the following equivalent expression


7x^2+2x-3-4x^2+3x-1

Now, we will group each coefficient separately. That is, we will group terms that have the same coefficient. If we do so, we obtain


(7-4)x^2+(2+3)\cdot x+(-3-1)\cdot1

Now, if we operate inside each parentheses, we obtain the final expression, which is


3x^2+5x-4

User Kbosak
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