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In Rectangle ABCD, diagonals AC and BD intersect at point P. If PD= 5x and AC = 130, solve for x.
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In Rectangle ABCD, diagonals AC and BD intersect at point P. If PD= 5x and AC = 130, solve for x.

User Uli Bethke
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1 Answer

1 vote

In a rectangle, the diagonals are equals. so,


\begin{gathered} 130=5x+(130)/(2) \\ x=(65)/(5)=13 \end{gathered}

The answer is x = 13

In Rectangle ABCD, diagonals AC and BD intersect at point P. If PD= 5x and AC = 130, solve-example-1
User ShaNnex
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5.9k points
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