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Express the product of 2x2 + 3x - 10 and x +5 in standard form.

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The given expression :


2x^2+3x\text{ -10 and x +5}

set up the expressions next to each other in parenthesis:


(x+5)(2x^2+3x-10)

Distribute the first term in the first set of parenthesis throughout each term in the second set of parenthesis:


(x+5)(2x^2+3x-10)=x(2x^2+3x-10)+5(2x^2+3x-10)

Now, distribute x over 2x^2+3x-10 and 5 too


\begin{gathered} (x+5)(2x^2+3x-10)=x(2x^2+3x-10)+5(2x^2+3x-10) \\ (x+5)(2x^2+3x-10)=2x^3+3x^2-10x+10x^2+15x-50 \\ (x+5)(2x^2+3x-10)=2x^3+13x^2+5x-50 \end{gathered}

User Istvan
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