We are given that a ball is dropped down a ramp and we are asked to determine the velocity and construct a velocity table.
To do that we need to use the following formula for velocity:
![v=(d)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/7bvf02ex7prlyl84jiizv8vikm7s8zddn1.png)
Where:
![\begin{gathered} v=\text{ velocity} \\ d=\text{ distance} \\ t=\text{ time} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ycejhbm4d4xx7c9gtoxvi1ghymnwsnuod2.png)
For example, for the case when the ball is stopped after 2 meters we determine the velocity by dividing the distance over the time, we get:
![v=(2m)/(1.21s)](https://img.qammunity.org/2023/formulas/physics/college/ifn5b4czmbdvua6rasn2bqs5uvx6nfe88r.png)
Solving the operations we get:
![v=1.7\text{ m/s}](https://img.qammunity.org/2023/formulas/physics/college/dsjzbapvawptf9z106xwc4tumu0iz65uqv.png)
Therefore, the velocity for this distance is 1.7 meters per second.
We repeat this operation for each of the distances with the corresponding time and construct a table of "time" vs "velocity", as follows:
To build the graph we plot the points of time and velocity, as follows: