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Calculate the amount or work done on a 25 N box that is lifted 1.5m off the floor. dont forget the units

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\begin{gathered} Given- \\ Force\text{ }acting\text{ }on\text{ }the\text{ }box=25N \\ height\text{ =1.5m} \end{gathered}
\begin{gathered} to\text{ find- The amount of work done on the box to lift it 1.5m above } \\ \text{ }the\text{ }ground \end{gathered}
\begin{gathered} W(work\text{ done\rparen=}\int F.ds \\ if\text{ force is constant then} \\ W=F.S \\ W=FScos\theta \\ here\text{ F=force acting on the object } \\ S=\text{ displacement of the object} \\ \theta=angle\text{ between the force on the object and displacement of the } \\ object \end{gathered}
\begin{gathered} put\text{ the value on the formula} \\ W=25N*1.5m*cos0\degree \\ since\text{ we are applying force in the upward direction } \\ and\text{ displacement too is in the upward direction so the angle between } \\ the\text{ force and the displacement is 0}\degree.\text{ }and\text{ }........(cos0\degree=1) \\ W=37.5J \\ \end{gathered}

So the amount of work done by us needed to displace the object at the

height of 1.5m is W=37.5J

User Tom Hartman
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