Given
The mass is

The power is

The initial velovcity is

The final velocity is

To find
Time taken by the car to go from 0 m/s to 10 m/s.
Step-by-step explanation
By work-energy theorem we have that
Work done is equal to the change in kinetic energy.
Thus,

Again work done can be written as

where t is the time
Equating the two equations we have,

Conclusion
The time taken is 4.504 s