Question

4y + 12 = 0Find two points on the line to be graphed

Answer 1

Given the line:

`4y+12=0`

We simplify to have:

`\begin{gathered} 4y=-12 \\ y=-(12)/(4) \\ y=-3 \end{gathered}`

The line y=-3 is a horizontal line passing through y=-3.

Two points on the line that can be graphed are:

`\begin{gathered} (1,-3) \\ (5,-3) \end{gathered}`

You can pick any value of x. The value of y has to remain constant.