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VMC · Answer 1 · 2023-05-26T15:06:42+0000

$\begin{gathered} f(x)=2^x \\ \\ a(2^(bx\pm h))\pm k \\ \\ a>1\text{vertical stretch } \\ 01\text{ horizontal compression} \\ 0Above you have a general explanation of the transformations on a exponential function, then, for the given fucntions you have the next transformations:[tex]g(x)=2^(x+1)-6$

1. translation 1 unit left and 6 units down

2. Stretch vertically by a factor of 6 and translate 1 unit down

3. Compress horizontally by a factor of 6 and translate 1 unit down

4. Translation 6 units left and 1 unit up

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