Question

What is the half life of an isotope that has a decay constant of 0.00567?

Answer 1

We are asked to determine the half-life of an isotope. To do that we will use the following formula:

`T=(ln(2))/(\lambda)`

Where:

`\begin{gathered} T=\text{ half-life} \\ \lambda=\text{ decay constant} \end{gathered}`

Now, we plug in the values:

`T=(ln(2))/(0.00567)`

Solving the operations:

`T=122.25`

Therefore, the half-life is 122.25