First equation
3(x−2)(x+3)=0
3 is multiplying on the left, then it will divide on the right.
(x−2)(x+3) = 0/3
(x−2)(x+3) = 0
The solutions are:
x - 2 = 0 or x + 3 = 0
that is, x = 2 and x = -3
Second equation
(2x−4)(3x+9) = 0
The solutions are:
2x − 4 = 0
x = 4/2
x = 2
or 3x+9 = 0
x = -9/3
x = -3
Then, they have the same solutions.