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Please help I feel like I get it buy I don't know the answer

Please help I feel like I get it buy I don't know the answer-example-1
User ApplePie
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To find the area of the figure you can find the area of the figures that make it up and then add these areas, in other words


A_f=A_r+A_R

Where

The formula to find the area of a rectangle is


\begin{gathered} A=l\cdot w \\ \text{ Where A is the area,} \\ \text{l is the length and} \\ w\text{ is the width of the rectangle } \end{gathered}

So, you have


\begin{gathered} l_r=3\text{ mm} \\ w_r=1\text{ mm} \\ A_r=l_r\cdot w_r \\ A_r=3\operatorname{mm}\cdot1\operatorname{mm} \\ A_r=3\operatorname{mm}^2 \end{gathered}


\begin{gathered} l_R=6\text{ mm} \\ w_R=2\text{ mm} \\ A_R=l_R\cdot w_R \\ A_R=6\operatorname{mm}\cdot2\operatorname{mm} \\ A_R=12\operatorname{mm}^2 \end{gathered}

Finally, adding the areas you have


\begin{gathered} A_f=A_r+A_R \\ A_f=3\operatorname{mm}^2+12\operatorname{mm}^2 \\ A_f=15\operatorname{mm}^2 \end{gathered}

Therefore, the area of the figure is 15 square milimeters.

Please help I feel like I get it buy I don't know the answer-example-1
User Linqu
by
7.8k points

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