Consider the given expression,
![y=82(1.045)^x](https://img.qammunity.org/2023/formulas/mathematics/college/otgz2ttzjjhfqudokh6lljmqlknc99sz3x.png)
The first derivative gives the rate of growth for the number of followers.
Solve for the first derivative as,
![\begin{gathered} (dy)/(dx)=82*(d \square)/(dx)(1.045)^x \\ (dy)/(dx)=82*(1.045)^x\ln (1.045) \\ (dy)/(dx)=y*0.045 \\ (dy)/(dx)=4.5\text{ percent of y} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yfd9wzkowb8sgppit3cr40h4xldcnakdeh.png)
Thus, the rate of growth of followers is approximately 4.5% each week.
Therefore, option C is the correct choice.
The number of followers corresponding to the 4th week is calculated as,
![y=82*(1.045)^4=82*1.1925=97.7865\approx98](https://img.qammunity.org/2023/formulas/mathematics/college/tcubogcozeertmbwux1w4vg364dgxix0j0.png)
Thus, Michael should expect approximately 98 followers in 4th week.