Question

Find the midpoint of the line segment with endpoints P1(11/2,3/8) and P2 (-7/2,5/8)

Answer 1

To find:

The midpoint of the line segment with the endpoints P1(11/2,3/8) and P2 (-7/2,5/8).

Solution:

The midpoint formula is:

`((x_1+x_2)/(2),(y_1+y_2)/(2))`

Put the values:

`\begin{gathered} (((11)/(2)-(7)/(2))/(2),((3)/(8)+(5)/(8))/(2))=(((4)/(2))/(2),((8)/(8))/(2)) \\ =((2)/(2),(1)/(2)) \\ =(1,(1)/(2)) \end{gathered}`

Thus, the midpoint is (1, 1/2).