Given
jenny mixed 4kg of mixed nuts containing 16% of peanuts with 12kg of mixed nuts containing 40% of peanuts .
Find
Percent in the new mixture of peanuts
Step-by-step explanation
we are given 4kg of mixed nuts containing 16% of peanuts
Amount of quantity =
![(percentage)/(100)* totalamount](https://img.qammunity.org/2023/formulas/mathematics/college/w93ecojwnbr7koa272hqomcv0vls7fugd1.png)
so,
![(16)/(100)*4=0.64kg](https://img.qammunity.org/2023/formulas/mathematics/college/d444angbxvq1dv2v96k0fpm7rcs9spjuyl.png)
and also 12kg of mixed nuts containing 40% of peanuts .
so,
![(40)/(100)*12=4.8kg](https://img.qammunity.org/2023/formulas/mathematics/college/qs16uqljz6uxv1xvm7wipbm4pefxbufcac.png)
so,total weight
![0.64+4.80=5.44kg](https://img.qammunity.org/2023/formulas/mathematics/college/jstuv2mpoi4nk2mxccnaehoa8s2umsvrnt.png)
let total mass pf mixture containing x % peanuts.
so,
![\begin{gathered} (5.44)/(16)=(x)/(100) \\ 34=x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/62jsg0a7dn0xie82gc1d4420a0kepe24iu.png)
Final Answer
Percent in the new mixture of peanuts = 34%