Question

Given a 10 sided figure how many diagonals can you draw from one vertex?

Answer 1

`\begin{gathered} The\text{ number of diagonals in the polygon is as follows:} \\ \text{Diagonals}=(n(n-3))/(2) \\ \text{Here, n is the number of sides} \\ So,\text{ } \\ \text{Diagonals}=(10(10-3))/(2) \\ \text{Diagonals}=(10*7)/(2) \\ \text{Diagonals}=35 \end{gathered}`