There are 360 degrees in a circle.
We can write:

Given, Arc LAM = 256°, we can find Arc MBL:

The central angle that subtends Arc MBL also measures 104 degrees.

We also know,

Angle MPB and Angle BPL are equal, so we have:

Now,
Arc LB subtends the central angle BPL, so they are same in measure.
Thus,
