Question

Since the equations for both triangles have a2 + b2, you can think of the two equations for c2 and n2 as a system of equations. Substitute what a2 + b2 equals in the first equation for a2 + b2 in the second equation. After you substitute, what equation do you get?

Answer 1

Given:

Given that a two triangles with

`\begin{gathered} c^2=a^2+b^2 \\ n^2=a^2+b^2 \end{gathered}`

Required:

To write the equation by substituting first equation in the second equation.

Step-by-step explanation:

Now consider,

`\begin{gathered} c^2=a^2+b^2----(1) \\ n^2=a^2+b^2----(2) \end{gathered}`

Now put the equation(2) in (1), we get

`\begin{gathered} n^2=c^2 \\ n^2-c^2=0 \end{gathered}`

Final Answer:

`n^2-c^2=0`