Question

Hi! Is it possible to get some help on this question?

Answer 1

Given that,

The measure of the rectangular lot is 7x by 7x

The measure of the sports field is 5x by 5x

Area of the lot left over is Area of the rectanglar lot-Area of the sports field

we get,

Area of the rectangle lot

`=7x*7x`

`=49x^2`

Area of the sports field is,

`=5x*5x`

`=25x^2`

Area of the lot left over to build bleachers is

`=49x^2-25x^2=24x^2`

Area of the lot left over to build bleachers is 24x^2 square units.