Question

Right in the Quetion of the circle the center (-6,8) and radius 11 XP

Answer 1

The equation of a circle with Center (h,k) and Radius = r is given by,

`(x-h)^2+(y-k)^2=r^2`

In our question, we are given,

Center = (-6, 8)

Radius = 11

We can substitute and figure out the equation of the circle as,

`\begin{gathered} (x-(-6))^2+(y-8)^2=11^2 \\ (x+6)^2+(y-8)^2=121 \end{gathered}`Answer
`(x+6)^2+(y-8)^2=121`