Question

Which expression shows the sum of 21 and 56 as the product of the GCFand a sum of two numbers with no common factor?3(7 + 56)7(5 + 6)7(3 + 8)7(21 + 56)

Answer 1

7 ( 3 + 8)

Step-by-step explanation:

First, let's find the greatest common factor between 21 and 56.

So, the factors of 21 and 56 are:

21: 1, 3, 7, 21

56: 1, 2, 4, 7, 8, 14, 28, 56

Then, the common factors are 1 and 7 and the greatest is 7. It means that the GCF of 21 and 56 is 7

Now, we need to write 21 and 56 as a product that includes the number 7 as:

21 = 7 x 3

56 = 7 x 8

Therefore, the sum of 21 and 56 can be written as:

21 + 56

(7 x 3) + (7 x 8)

So, applying the distributive property, we get:

(7 x 3) + (7 x 8) = 7 ( 3 + 8 )

Therefore, the answer is 7(3 + 8)

Because 7 is the GCF and 3 and 8 are two number with no common factor