Solving Quadratic Equations
The general form of a quadratic equation is:

It can be solved by using the formula:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
we have the following equation:

we need to put this equation in standard form as explained above
Adding 2x^2:

Now we have the equation in the correct form, we find the value of the variables as follows:
a=1, b=-7, c=7
Applying the formula:
![x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(1)(7)}}{2(1)}](https://img.qammunity.org/2023/formulas/mathematics/college/1iflve0kulvpmplixg5gwdabn5hd0wpgxe.png)
Operating:
![x=\frac{7\pm\sqrt[]{49-28}}{2}=\frac{7\pm\sqrt[]{21}}{2}](https://img.qammunity.org/2023/formulas/mathematics/college/xo59nfwxea4xw1024hwb3sjmk2fqyewbow.png)
The square root of 21 is not exact, we use two decimals so far, and we'll round to one decimal at the very last time.
Taking the square root:

The solutions (to the nearest tenth) are:
x= 7.8
x=1.2
Answer complete
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