Question

In a isosceles triangle. one angle is 9° greater than each of the other two equal angles. find the measure of all three angles

Answer 1

In a isosceles triangle. one angle is 9° greater than each of the other two equal angles. find the measure of all three angles

suppose the 'other two angles' measure =x degrees. then the first-mentioned angle has to measure = x+9

Sum of the angle in a triangle = 180°

`\begin{gathered} 9+x+x+x\text{ = 180} \\ 9+3x=180 \\ 3x=180-9 \\ 3x=171 \\ x=(171)/(3) \\ x=57^0 \end{gathered}`

Therefore the measure of all the three angle will be

57 , 57 , 57+9 = 66

Hence the final answer are 57 , 57 and 66