Question

Assuming the mass of the ice in the beaker was 2000 g (2 kg), calculate the amount of heat that must have been added to convert the ice to water (assume that the entire 2000 g was ice at the start of melting, and the entire 2000 g was water at the end of the melting). Assume that the change took place entirely at 0 °C. The heat of fusion (DHfus) for H2O is 334 J/g.H2O(s) --> H2O(l) DHfus = 334 J/g

Answer 1

In this question, we need to calculate the amount of heat needed to melt ice into water, and the way of doing that is by using the calorimetry formula, but now we are going to use it in terms of melting, the formula will be:

Q = m * ΔHfusion

We have:

m = 2000 grams

ΔHfusion = 334 J/g

Now we add these values into the formula:

Q = 2000 * 334

Q = 668000 Joules or 66.8 Kilojoules