Question

Which function of x would have zeros of 1/3 and -5?

Answer 1

The functions of x with zeros of 1/3 and -5

`\begin{gathered} x\text{ = }(1)/(3)\text{ and x = -5} \\ (x\text{ - }(1)/(3))\text{ and (x + 5)} \\ \end{gathered}`
`\begin{gathered} (x\text{ -}(1)/(3))(x\text{ + 5)} \\ x^2\text{ + 5x - }(x)/(3)\text{ - }(5)/(3) \\ \text{ multiply through by 3} \\ 3x^2\text{ + 15x - x - 5} \\ 3x^2\text{ + 14x - 5} \\ F(x)\text{ = }3x^2\text{ + 14x - 5} \end{gathered}`

Hence the functions of x with zeros of 1/3 and -5 = 3x² + 14x - 5