Question

Divide the monomials 20m^5n^2/30m^3n^9

Answer 1

`(2m^2)/(3n^7)`

Step-by-step explanation

Given monomials:

`(20m^5n^2)/(30m^3n^9)`

Using division law of indices:

`\begin{gathered} (20)/(30)*(m^5)/(m^3)*(n^2)/(n^9)=(2)/(3)* m^(5-3)* n^(2-9) \\ =(2)/(3)* m^2* n^(-7) \\ \end{gathered}`

Now, using the negative exponent law of indices, we have:

`(2)/(3)* m^2*(1)/(n^7)=(2* m^2*1)/(3* n^7)=(2m^2)/(3n^7)`