Question

Solve on the interval [0, 2pi):3 sec x - 2 = 13 sec x =3secx= 1cos = -1Is it 0?

Answer 1

3 sec x - 2 = 1

Add 2 to both sides

3 sec x = 1+ 2

3 sec x = 3

divide both sides by 3

sec x = 3/3

sec x = 1

`\begin{gathered} \text{ sec x = 1} \\ x=sec^(-1)1 \\ x\text{ = 0 } \\ \text{and also, the interval is \lbrack{}0, 2}\pi\rbrack \\ x\text{ = 2}\pi \\ \text{The answer is x = 0 and x = 2}\pi \end{gathered}`