the Given:
The expression is given as,
![y=\sqrt[]{x+7}\text{ . . . . . (1)}](https://img.qammunity.org/2023/formulas/mathematics/college/pj7e6pzenipo3heim569mdge31qswh6dbk.png)
The value of dx/dt is,

The objective is to find dy/dt at y = 6.
Step-by-step explanation:
Substitute y = 6 in equation (1),
![\begin{gathered} y=\sqrt[]{x+7} \\ 6=\sqrt[]{x+7}\text{ . . . . (3)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gejk0yxud4smynz32xsi3unlxd77oc7kps.png)
To find dy/dt:
Differentiate equation (1) for t.
![\begin{gathered} \frac{dy}{d\text{t}}=\frac{dy}{d\text{x}}*\frac{d\text{x}}{dt} \\ =\frac{d}{d\text{x}}\sqrt[]{x+7}*\frac{d\text{x}}{\mathrm{d}t} \\ =\frac{1}{2\sqrt[]{x+7}}*\frac{d\text{x}}{\mathrm{d}t}\text{ . . . . .(4)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/h95gyq8wggjirqwlm9hsxhhpdca43k3xak.png)
Substitute the value of equations (2) and (3) in equation (4).
![\begin{gathered} \frac{d\text{ y}}{d\text{ t}}=\frac{1}{2\sqrt[]{x+7}}*\frac{d\text{ x}}{d\text{ t}} \\ =(1)/(2*6)*7 \\ =(7)/(12) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9zxlblhdkftyavvu0zv7ai5imtaq6cb8tu.png)
Hence, the value of the rate of change is 7/12.